๐Ÿงฉ Algorithm/[BOJ] Bronze

BOJ 2675๋ฒˆ : ๋ฌธ์ž์—ด ๋ฐ˜๋ณต (C++/Python/Bronze 2)

devCloud 2022. 8. 6. 19:57
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2675๋ฒˆ: ๋ฌธ์ž์—ด ๋ฐ˜๋ณต

๋ฌธ์ž์—ด S๋ฅผ ์ž…๋ ฅ๋ฐ›์€ ํ›„์—, ๊ฐ ๋ฌธ์ž๋ฅผ R๋ฒˆ ๋ฐ˜๋ณตํ•ด ์ƒˆ ๋ฌธ์ž์—ด P๋ฅผ ๋งŒ๋“  ํ›„ ์ถœ๋ ฅํ•˜๋Š” ํ”„๋กœ๊ทธ๋žจ์„ ์ž‘์„ฑํ•˜์‹œ์˜ค. ์ฆ‰, ์ฒซ ๋ฒˆ์งธ ๋ฌธ์ž๋ฅผ R๋ฒˆ ๋ฐ˜๋ณตํ•˜๊ณ , ๋‘ ๋ฒˆ์งธ ๋ฌธ์ž๋ฅผ R๋ฒˆ ๋ฐ˜๋ณตํ•˜๋Š” ์‹์œผ๋กœ P๋ฅผ ๋งŒ๋“ค๋ฉด ๋œ๋‹ค

www.acmicpc.net

๋ฌธ์ œ

๋ฌธ์ž์—ด S๋ฅผ ์ž…๋ ฅ๋ฐ›์€ ํ›„์—, ๊ฐ ๋ฌธ์ž๋ฅผ R๋ฒˆ ๋ฐ˜๋ณตํ•ด ์ƒˆ ๋ฌธ์ž์—ด P๋ฅผ ๋งŒ๋“  ํ›„ ์ถœ๋ ฅํ•˜๋Š” ํ”„๋กœ๊ทธ๋žจ์„ ์ž‘์„ฑํ•˜์‹œ์˜ค. ์ฆ‰, ์ฒซ ๋ฒˆ์งธ ๋ฌธ์ž๋ฅผ R๋ฒˆ ๋ฐ˜๋ณตํ•˜๊ณ , ๋‘ ๋ฒˆ์งธ ๋ฌธ์ž๋ฅผ R๋ฒˆ ๋ฐ˜๋ณตํ•˜๋Š” ์‹์œผ๋กœ P๋ฅผ ๋งŒ๋“ค๋ฉด ๋œ๋‹ค. S์—๋Š” QR Code "alphanumeric" ๋ฌธ์ž๋งŒ ๋“ค์–ด์žˆ๋‹ค.

QR Code "alphanumeric" ๋ฌธ์ž๋Š” 0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ$%*+-./: ์ด๋‹ค.

 

์ž…๋ ฅ

์ฒซ์งธ ์ค„์— ํ…Œ์ŠคํŠธ ์ผ€์ด์Šค์˜ ๊ฐœ์ˆ˜ T(1 ≤ T ≤ 1,000)๊ฐ€ ์ฃผ์–ด์ง„๋‹ค. ๊ฐ ํ…Œ์ŠคํŠธ ์ผ€์ด์Šค๋Š” ๋ฐ˜๋ณต ํšŸ์ˆ˜ R(1 ≤ R ≤ 8), ๋ฌธ์ž์—ด S๊ฐ€ ๊ณต๋ฐฑ์œผ๋กœ ๊ตฌ๋ถ„๋˜์–ด ์ฃผ์–ด์ง„๋‹ค. S์˜ ๊ธธ์ด๋Š” ์ ์–ด๋„ 1์ด๋ฉฐ, 20๊ธ€์ž๋ฅผ ๋„˜์ง€ ์•Š๋Š”๋‹ค.

 

์ถœ๋ ฅ

๊ฐ ํ…Œ์ŠคํŠธ ์ผ€์ด์Šค์— ๋Œ€ํ•ด P๋ฅผ ์ถœ๋ ฅํ•œ๋‹ค.


์˜ˆ์ œ ์ž…๋ ฅ

2
3 ABC
5 /HTP

์˜ˆ์ œ ์ถœ๋ ฅ

AAABBBCCC
/////HHHHHTTTTTPPPPP

Solution

C++

#include <iostream>
#include <string>
using namespace std;

int main() {
    int T, R;
    string S;
    cin >> T;
    for(int i=0; i < T; i++){
        cin >> R >> S;
        for(int i=0; i < S.length(); i++){
            for(int j=0; j < R; j++)
                cout << S[i]; //์—ฌ๊ธฐ์„œ ์•ฝ๊ฐ„ ๋ง‰ํž˜
        }
        cout << "\n";
    }
    return 0;
}

Python

t = int(input())
for i in range(t):
    r, s = input().split() #๊ณต๋ฐฑ์„ ๊ธฐ์ค€์œผ๋กœ ์ž…๋ ฅ
    for i in s:
        print(int(r)*i, end='') #end = ' ' ์˜†์— ๋ถ™์ธ๋‹ค.
    print()
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